如何在不使用Java知道键的情况下解析JSON对象? [英] How to parse JSON object without knowing key using java?

问题描述

在下面的JSON对象中，我想在不知道键名的情况下进行解析. 对象中还包含另一个对象.

In the below JSON object I want to parse without knowing key name. object also contains another object within it.

{状态":确定"，描述":请求原为 成功.，"帐户:{" renewal_upper_limit:0，" id:10066，" email:" [e-mail]，" full_name:" Raj，"电话:" 99000000，" format_time:"美国，" format_date:"亚洲，" reports_time_range:" 24 小时"，"dashboard_time_range":"24H"}}

{"status":"ok","description":"Request was successful.","account":{"renewal_upper_limit":0,"id":10066,"email":"[e-mail]","full_name":" Raj","phone":"99000000","format_time":"America","format_date":"Asia","reports_time_range":"24 hours","dashboard_time_range":"24H"}}

推荐答案

Json Object就像Map一样，您可以像这样迭代它:

Json Object is just like a Map, you can iterate it like this:

    JSONObject parse = JSON.parseObject("");
    for (Map.Entry<String, Object> entry : parse.entrySet()) {
        System.out.println(entry.getKey() + "=" + entry.getValue());
    }

fastjson在此处可用: https://github.com/alibaba/fastjson

fastjson is available here:https://github.com/alibaba/fastjson

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