处理JSON提要中的数据以显示它 [英] Manipulating data from a JSON feed to display it

问题描述

{
  "Group": [
    {
      "name": "HolderOne",
      "operators": [
          {
           "username": "ken",
           "status": 3
          },
         .....etc.....

我尝试操作的JSON提要必须在上面设置格式.

The JSON feed I am attempting to manipulate has to format above.

我希望能够显示用户名和状态.

I wish to be able to display username and status.

$json = file_get_contents("urlhere");
$obj=json_decode($json);
echo $obj->username;
echo $obj->status;

这显然不起作用，因为它们在供稿中嵌套了(?)...我尝试过:

This obviously doesn't work as they are nested(?) within the feed...I have tried:

$obj->Group[0]->name->operators->username

和

$obj->Group[0]->name->username

无济于事(以及带有，true和['name']的json_decode等).

to no avail (as well as json_decode with ,true and ['name'], etc).

我特别昏暗吗?

当我执行var转储时，可以从feed中收集数据了.

when I do a var dump, the data is being collected from the feed okay.

推荐答案

弄清这一点的最好方法是迭代地执行print_r的操作:

The best way to figure this out is to iteratively do print_r's:

print_r($obj)
//prints what you see above
print_r($obj['Group']
//prints the Group Object
print_r($obj['Group'][0])
//prints first element in Group Object
print_r($obj['Group'][0]['operators'])
//etc.....

这就是我发现遇到困难时如何访问这些 deep 元素的方法.虽然在我看来您想要:

That's how I find out how to access these deep elements if I get a little stuck. Though it appears to me that you want:

$obj->Group[0]->operators[0]->username

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