Java:如何“重新启动"静态类? [英] Java: how to "restart" a static class?

问题描述

我有一个静态类(Foo)和一个主类(Main)

I have a static class (Foo) and a main class (Main)

请参阅Main.java:

See Main.java:

public class Main {

    public static void main(String[] args) {
        System.out.println(Foo.i); // 0
        Foo.i++;
        System.out.println(Foo.i); // 1
        // restart Foo here 
        System.out.println(Foo.i); // 1 again...I need 0
    }

}

请参阅Foo.java:

See Foo.java:

public class Foo {

    public static int i = 0;

}

有什么方法可以重新启动或重置静态类?

Is there any way to restart or reset a static class?

注意:我需要这样做是因为我正在用jUnit测试静态类，并且需要在第二次测试之前清除参数.

Note: I need this because I'm testing a static class with jUnit and I need to clean parameters before second test.

编辑

ALMOST解决方案:

使用StanMax答案，我可以这样做:

Using StanMax answer, I can to this:

Main.java

public class Main {

    public static void main(String[] args) throws Exception {
        test();
        test();
    }

    public static void test() throws Exception {

        System.out.println("\ntest()");

        MyClassLoader myClassLoader = new MyClassLoader();
        Class<?> fooClass = myClassLoader.loadClass(Foo.class.getCanonicalName());

        Object foo = fooClass.newInstance();
        System.out.println("Checking classloader: " + foo.getClass().getClassLoader());

        System.out.println("GC called!");
        System.gc();
    }

}

MyClassLoader.java

public class MyClassLoader {

    private URLClassLoader urlClassLoader;

    public MyClassLoader() {
        try {
            URL url = new File(System.getProperty("user.dir") + "/bin/").toURL();
            URL[] urlArray = {url};  
            urlClassLoader = new URLClassLoader(urlArray, null);  
        } catch (Exception e) {
        }
    }

    public Class<?> loadClass(String name) {
          try {
            return (Class<?>) urlClassLoader.loadClass(name);
        } catch (Exception e) {
        }
        return null;
    }

    @Override
    protected void finalize() throws Throwable {
        System.out.println("MyClassLoader - End.");     
    }


}

Foo.java

public class Foo {

    public static int i = 0;

    static {
        System.out.println("Foo - BEGIN ---------------------------------");
    }

    public void finalize() throws Throwable {
        System.out.println("Foo - End.");
    }


}

输出

test()
Foo - BEGIN ---------------------------------
Checking classloader: java.net.URLClassLoader@ec160c9
GC called!
MyClassLoader - End.
Foo - End.

test()
Foo - BEGIN ---------------------------------
Checking classloader: java.net.URLClassLoader@ec3fb9b
GC called!
MyClassLoader - End.
Foo - End.

问题:，如果我在下面进行投射:

PROBLEM: if I do the cast bellow:

Foo foo = (Foo) fooClass.newInstance();

我收到错误消息:

java.lang.ClassCastException

推荐答案

仅当您可以卸载类时，才重新加载它，因为在加载类时将执行类静态代码.

Only if you can unload class, get it re-loaded, as class static code gets executed when class is loaded.

但是您可以直接修改值:

But you can just directly modify the value:

Foo.i = 0;

(或创建等效的方法，尤其是在静态成员不是公共成员的情况下)

(or create equivalent method for doing it, esp. if static member is not public)

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