Tensorflow-ValueError:模型的输出张量必须是TensorFlow`Layer`的输出 [英] Tensorflow - ValueError: Output tensors to a Model must be the output of a TensorFlow `Layer`
问题描述
我已经在TensorFlow 2.0中使用Keras功能API创建了一个RNN,以下代码可以在其中运行
I have created an RNN with the Keras functional API in TensorFlow 2.0 where the following piece of code workes
sum_input = keras.Input(shape=(UNIT_SIZE, 256,), name='sum')
x = tf.unstack(sum_input,axis=2, num=256)
t_sum = x[0]
for i in range(len(x) - 1):
t_sum = keras.layers.Add()([t_sum, x[i+1]])
sum_m = keras.Model(inputs=sum_input, outputs=t_sum, name='sum_model')
然后我不得不更改为Tensorflow 1.13,这给了我以下错误
I then had to changed to Tensorflow 1.13 which gives me the following error
ValueError: Output tensors to a Model must be the output of a TensorFlow `Layer` (thus holding past layer metadata). Found: Tensor("add_254/add:0", shape=(?, 40), dtype=float32)
我不明白为什么输出张量不是来自Tensorflow层,因为t_sum是来自keras.layers.Add的输出.
I don't understand why the output tensor is not from a Tensorflow layer, since t_sum is the output from keras.layers.Add.
I have tried to wrap parts of the code into keras.layers.Lambda as suggested in ValueError: Output tensors to a Model must be the output of a TensorFlow Layer , but it doesn't seem to work for me.
推荐答案
问题不是与Add()
层有关,而是与tf.unstack()
有关-它不是keras.layers.Layer()
的实例.您可以将其包装为自定义图层:
The problem is not with Add()
layer but with tf.unstack()
- it is not an instance of keras.layers.Layer()
. You can just wrap it up as custom layer:
import tensorflow as tf
class Unstack(tf.keras.layers.Layer):
def __init__(self):
super(Unstack, self).__init__()
def call(self, inputs, num=256):
return tf.unstack(inputs, axis=2, num=num)
x = Unstack()(sum_input)
或者,您可以使用Lambda
层来代替子类化:
or, instead of subclassing, you can do it using Lambda
layer:
x = tf.keras.layers.Lambda(lambda t: tf.unstack(t, axis=2, num=256))(sum_input)
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