Python:如何使用不区分大小写的attrgetter对对象列表进行排序 [英] Python: How to sort a list of objects using attrgetter with case insensitivity

问题描述

self.data = sorted(self.data, key=attrgetter('word'))

self.data是Word对象的列表.单词对象具有单词"，定义"，示例"和难度"属性.我想按每个Word对象的'word'字符串进行排序，上面的代码可以做到这一点，只是它不区分大小写.我该如何使排序不区分大小写?

self.data is a list of Word objects. Word objects have 'word', 'definition', 'example' and 'difficulty' attributes. I want to sort by the 'word' strings of each Word object, and the code above does that except it's not case insensitive. How would I go about making the sorting case insensitive?

我已经尝试过在此处问到的另一个问题的解决方案，但是当我尝试时，它说"TypeError:'Word'对象不可下标".我该怎么做才能使其正常工作?

I've tried the solutions from another question asked here, but when I tried it, it said "TypeError: 'Word' object is not subscriptable". What could I do to make it work?

谢谢.

推荐答案

您可以编写自己的key函数:

You can write your own key function:

self.data = sorted(self.data, key = lambda w: w.word.lower())

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