SendInput在Windows 8(64位)中不起作用,但在Windows 7(32位)中起作用 [英] SendInput does not work in Windows 8(64 bit) but work in Windows 7(32bit)
本文介绍了SendInput在Windows 8(64位)中不起作用,但在Windows 7(32位)中起作用的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我写了程序将sendInput发送到游戏和桌面应用程序,而不是从键盘上获取输入.结果是:
I wrote program to sendInput to games and desktop applications instead of taking input from keyboard.This is the result:
Windows 7(32位):在游戏和桌面应用程序中完美运行.
Windows 7 (32 bit) : worked perfect in games and desktop applications.
Windows 8(64位):DID在游戏中不起作用,但在notepad.exe中起作用.
Windows 8 (64 bit) : DID NOT work in games but worked in notepad.exe.
那么为什么它在Win 8中不起作用?
so Why it did not work with win 8 ?
这是代码:
[StructLayout(LayoutKind.Sequential)]
struct MOUSEINPUT
{
public int dx;
public int dy;
public uint mouseData;
public uint dwFlags;
public uint time;
public IntPtr dwExtraInfo;
}
[StructLayout(LayoutKind.Sequential)]
struct KEYBDINPUT
{
public ushort wVk;
public ushort wScan;
public uint dwFlags;
public uint time;
public IntPtr dwExtraInfo;
}
[StructLayout(LayoutKind.Sequential)]
struct HARDWAREINPUT
{
public int uMsg;
public short wParamL;
public short wParamH;
}
[StructLayout(LayoutKind.Explicit)]
struct MouseKeybdHardwareInputUnion
{
[FieldOffset(0)]
public MOUSEINPUT mi;
[FieldOffset(0)]
public KEYBDINPUT ki;
[FieldOffset(0)]
public HARDWAREINPUT hi;
}
[StructLayout(LayoutKind.Sequential)]
struct INPUT
{
public uint type;
public MouseKeybdHardwareInputUnion mkhi;
}
enum SendInputFlags
{
KEYEVENTF_EXTENDEDKEY = 0x0001,
KEYEVENTF_KEYUP = 0x0002,
KEYEVENTF_UNICODE = 0x0004,
KEYEVENTF_SCANCODE = 0x0008,
}
[DllImport("user32.dll")]
static extern UInt32 SendInput(UInt32 nInputs, [MarshalAs(UnmanagedType.LPArray, SizeConst = 1)] INPUT[] pInputs, Int32 cbSize);
public static void StrokeKey(ushort codeOfKey)
{
INPUT[] InputData = new INPUT[1];
ushort ScanCode = codeOfKey;
InputData[0].type = 1;
InputData[0].mkhi.ki.wScan = (ushort)ScanCode;
InputData[0].mkhi.ki.dwFlags = (uint)SendInputFlags.KEYEVENTF_SCANCODE;
if (SendInput(1, InputData, Marshal.SizeOf(InputData[0])) == 0)
{
String blad = "SendInput failed with code: " + Marshal.GetLastWin32Error().ToString();
System.Diagnostics.Debug.WriteLine(blad);
}
}
public static void ReleaseKey(ushort codeOfKey)
{
INPUT[] InputData = new INPUT[1];
ushort ScanCode = codeOfKey;
InputData[0].type = 1;
InputData[0].mkhi.ki.wScan = (ushort)ScanCode;
InputData[0].mkhi.ki.dwFlags = (uint)SendInputFlags.KEYEVENTF_KEYUP | (uint)SendInputFlags.KEYEVENTF_SCANCODE;
InputData[0].mkhi.ki.time = 0;
InputData[0].mkhi.ki.dwExtraInfo = IntPtr.Zero;
SendInput(1, InputData, Marshal.SizeOf(InputData[0]));
}
推荐答案
最有可能的指针大小在大小为4的32位上在大小为8的64位上不同
most likely pointersize is different on 32 bits its size 4 on 64 bits its size 8
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