如何使用给定的列作为键和值来创建字典 [英] How to create a dictionary with columns given as keys and values

问题描述

好的，所以我得到了两列

Ok so I am given two columns

A S

A T

A Z

B F

B G

B P

B U

C D

C P

C R

D M

E H

F S

H U

第一列是点的列表，第二列是点的邻居的列表.我想把它做成字典，以便 {A:'S'，'T'，'Z'，B:'F'，'G'，'P'等}，等等.

The 1st column is a list of points, and the second column is the list of the neighbors of the points. I would like to make it a dictionary so that {A:'S','T','Z', B:'F','G','P' etc} and so on.

鉴于文本文件是两列，我尝试这样做的是

What I have tried doing is this, given that the text file is the two columns.

edges = open('romEdges.txt')

edgeslist = edges.read().split()

edgeskeys = edgeslist[::2]

edgesvalues = edgeslist[1::2]


dictionary = {}

for items in edgeskeys:

    dictionary[items]=[]

dictionary = OrderedDict(sorted(dictionary.items(), key=lambda t: t[0]))

for items in edgeskeys:

    if edgeskeys[items]==dictionary[items]:

        print()

print(dictionary)

我尝试制作2个列表，1个键和1个值，并尝试将它们与字典进行比较，等等，但我做对了！

I have tried making 2 lists, 1 of keys and 1 of values, and tried comparing them to the dictionary, etc, and I just can't get it right!

有一种简单的方法.

请帮助.

推荐答案

对于只想从列中创建简单字典而又不重复键值的人们来说，这应该可行:

For People who just want to create a simple dictionary from colums without recurring keyvalues this should work:

 edges = open('romEdges.txt')
 dict = {line[:1]:line[1:] for line in edges}
 print dict
 edges.close()

现在您的值中可能包含一些空格或退格符，那么您可以使用空字符串替换()

now you have possibly some whitespaces or Backspaces in the values, then you can replace() that with empty strings:

 edges = open('romEdges.txt')
 dict = {line[:1]:line[1:].split()[0] for line in edges}
 print dict
 edges.close()

如果您有多个列，并且希望从以下列中找到该键值的列表:

if you have multiple colums, and you want to have a list out of the following colums to that keyvalue:

 edges = open('romEdges.txt')
 dict = {line[:1]:line[1:].split() for line in edges}
 print dict
 edges.close()

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