如何创建基于键的合并值的字典？ [英] How to Create a Dictionary Merging Values Based on Keys?

问题描述

我需要创建一个将键映射到合并值的字典。
假设我有重复的键 40 ： {40： lamb} ， {40：狗} ， {50：鸡}

I need to create a dictionary mapping a keys to merged values. Let's say I got key value pairs with a duplicated key 40: {40: "lamb"}, {40: "dog"}, {50: "chicken"}

list_key = (40, 40, 50)
new_value = ("lamb", "dog", "chicken")

new_dict = {}
for i in list_key:
    if i not in new_dict:
        new_dict[list_key] = new_value
    else:
        new_dict[?] = new_value

return new_dict

这就是我遇到的问题。

我需要的是 {40 ：（小羊，狗），50 ：（鸡）} 。
如何获取？

What i need is {40: ("lamb", "dog"), 50: ("chicken")}. How can I get this?

推荐答案

一种方法是在不存在键的情况下创建列表。然后，只要您遇到相关的密钥，就添加到该列表中。

One way is to create a list if the key doesn't exist. Then, just append to that list whenever you encounter a relevant key.

keys = [40, 40, 50]
values = ["lamb", "dog", "chicken"]
d = {}

for k, v in zip(keys, values):
    if k not in d:
        d[k] = []
    d[k].append(v)

...尽管您可以使用 collections.defaultdict 更简洁地完成此操作：

...Though you can do this more prettily with collections.defaultdict:

keys = [40, 40, 50]
values = ["lamb", "dog", "chicken"]
d = defaultdict(lambda: [])

for k, v in zip(keys, values):
    d[k].append(v)

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