如何创建无限间隔的Observable,它将在每个时间间隔发出新的Object? [英] How to create infinite interval Observable that will emit new Object every time interval?
本文介绍了如何创建无限间隔的Observable,它将在每个时间间隔发出新的Object?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试创建一个Observable,它将每秒发出一个新对象. 所以现在我只压缩一个Observable,它从列表中发射有限数量的对象,间隔为Observable.
I am trying to create an Observable that will emit new object every second. So for now i am just zipping one Observable, which emits finite number of objects from a list, with interval Observable.
val list1 = mutableListOf<SomeClass1>(
SomeClass1("1", 1), SomeClass1("2", 2), SomeClass1("3", 3),
SomeClass1("4", 4), SomeClass1("5", 5), SomeClass1("6", 6),
SomeClass1("7", 7), SomeClass1("8", 8), SomeClass1("9", 9)
)
val someClass1Observable = Observable
.fromIterable(list1)
.zipWith(Observable.interval(2, TimeUnit.SECONDS),
BiFunction { item: SomeClass1, _: Long -> item })
那么,如何以每2秒就有一个带有某些参数的,名为SomeClass1类的新对象的方式实际实现此无限化?
So how to actually make this infinite, in a way that every 2 second there will be emiited new object of class SomeClass1 with some parameters?
推荐答案
以下是我的问题的答案,它满足了我的要求:
Here is the answer for my question, that satisfies my:
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_main)
var counter = 0
val periodicSomeClass1 = Observable.interval(1, TimeUnit.SECONDS)
.flatMap(
{
counter++
Observable.just(SomeClass1("$counter", counter))
}
)
periodicSomeClass1.subscribe { t: SomeClass1 -> Log.v("periodicSomeClass1", t.toString()) }
}
这篇关于如何创建无限间隔的Observable,它将在每个时间间隔发出新的Object?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文