如何在ksh中某个字符串之后提取子字符串? [英] How can I extract a substring after a certain string in ksh?

问题描述

如果我有这样的字符串:

If I have a string like this:

The important variable=123 the rest is not important.

我想在ksh中提取"123"部分.

I want to extract the "123" part in ksh.

到目前为止，我已经尝试过:

So far I have tried:

print awk ' {substr($line, 20) }' | read TEMP_VALUE

(这20部分只是临时的，直到我弄清楚如何提取字符串的起始位置.)

(This 20 part is just temporary, until I work out how to extract the start position of a string.)

但这只是打印awk ' {substr($line, 20) }' | read TEMP_VALUE(尽管此格式可以用于以下代码:print ${line} | awk '{print $1}' | read SINGLE_FILE).

But this just prints awk ' {substr($line, 20) }' | read TEMP_VALUE (though this format does work with code like this: print ${line} | awk '{print $1}' | read SINGLE_FILE).

我是否缺少执行此操作的简单命令(即其他语言)?

Am I missing a simple command to do this (that is in other languages)?

运行Solaris 10.

Running Solaris 10.

推荐答案

您的命令失败有多种原因:您需要类似

Your command is failing for multiple reasons: you need something like

TEMP_VALUE=$(print "$line" | awk '...')

您可以使用ksh参数扩展:

You can use ksh parameter expansion though:

line="The important variable=123 the rest is not important."
tmp=${line#*=}   # strip off the stuff up to and including the equal sign
num=${tmp%% *}   # strip off a space and all following the first space
print $num       # ==> 123

在ksh手册页中查找参数替换".

Look for "parameter substitution" in the ksh man page.

这篇关于如何在ksh中某个字符串之后提取子字符串?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！