吞食:处理400个错误的请求 [英] Guzzle: handle 400 bad request
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问题描述
我正在Laravel 4中使用Guzzle从另一台服务器返回一些数据,但是我无法处理Error 400错误请求
I'm using Guzzle in Laravel 4 to return some data from another server, but I can't handle Error 400 bad request
[status code] 400 [reason phrase] Bad Request
使用:
$client->get('http://www.example.com/path/'.$path,
[
'allow_redirects' => true,
'timeout' => 2000
]);
如何解决? 谢谢,
推荐答案
如Guzzle官方文档中所述: http: //guzzle.readthedocs.org/en/latest/quickstart.html
As written in Guzzle official documentation: http://guzzle.readthedocs.org/en/latest/quickstart.html
如果将例外请求选项设置为true,则会抛出GuzzleHttp \ Exception \ ClientException,引发400个级别的错误
A GuzzleHttp\Exception\ClientException is thrown for 400 level errors if the exceptions request option is set to true
为正确处理错误,我将使用以下代码:
For correct error handling I would use this code:
use GuzzleHttp\Client;
use GuzzleHttp\Exception\RequestException;
try {
$response = $client->get(YOUR_URL, [
'connect_timeout' => 10
]);
// Here the code for successful request
} catch (RequestException $e) {
// Catch all 4XX errors
// To catch exactly error 400 use
if ($e->getResponse()->getStatusCode() == '400') {
echo "Got response 400";
}
// You can check for whatever error status code you need
} catch (\Exception $e) {
// There was another exception.
}
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