PHP:用逗号(，)分割字符串，但忽略方括号内的任何内容? [英] PHP: Split a string by comma(,) but ignoring anything inside square brackets?

问题描述

如何用,拆分字符串，但是跳过数组内部的字符串

How do I split a string by , but skip the one that's inside an array

字符串-'=='，['abc'，'xyz']，1"

String - "'==', ['abc', 'xyz'], 1"

当我执行explode(',', $expression)时，它会给我4个数组

When I do explode(',', $expression) it's giving me 4 item in array

array:4 [
   0 => "'=='"
   1 => "['abc'"
   2 => "'xyz']"
   3 => 1
]

但是我希望输出为-

array:3 [
   0 => "'=='"
   1 => "['abc', 'xyz']"
   2 => 1
]

推荐答案

是的，正则表达式-选择所有逗号，忽略方括号

yeah, regex - select all commas, ignore in square brakets

/[,]+(?![^\[]*\])/g

https://regexr.com/3qudi

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