regexp用逗号和空格分隔字符串，但忽略内部引号和括号 [英] regexp split string by commas and spaces, but ignore the inside quotes and parentheses

问题描述

我需要用逗号和空格分隔字符串，但忽略内部引号，单引号和括号

I need split string by commas and spaces, but ignore the inside quotes, single quotes and parentheses

$str = "Questions, \"Quote\",'single quote','comma,inside' (inside parentheses) space #specialchar";

以使结果数组具有

[0]Questions
[1]Quote
[2]single quote
[3]comma,inside
[4]inside parentheses
[5]space
[6]#specialchar

我的常规正则表达式是

$tags = preg_split("/[,\s]*[^\w\s]+[\s]*/", $str,0,PREG_SPLIT_NO_EMPTY);

但是这忽略了特殊的字符，并且斯蒂尔将引号内的逗号分开，结果数组为:

but this is ignoring special chars and stil split the commas inside quotes, the resultant array is :

[0]Questions
[1]Quote
[2]single quote
[3]comma
[4]inside
[5]inside parentheses
[6]space
[7]specialchar

ps:这不是csv

ps: this is no csv

非常感谢

推荐答案

这仅适用于非嵌套括号:

This will work only for non-nested parentheses:

    $regex = <<<HERE
    /  "  ( (?:[^"\\\\]++|\\\\.)*+ ) \"
     | '  ( (?:[^'\\\\]++|\\\\.)*+ ) \'
     | \( ( [^)]*                  ) \)
     | [\s,]+
    /x
    HERE;

    $tags = preg_split($regex, $str, -1,
                         PREG_SPLIT_NO_EMPTY
                       | PREG_SPLIT_DELIM_CAPTURE);

++和*+将消耗尽可能多的能量，并且不退回任何东西进行回溯. perlre(1)中描述了这种技术，它是进行这种匹配的最有效方法.

The ++ and *+ will consume as much as they can and give nothing back for backtracking. This technique is described in perlre(1) as the most efficient way to do this kind of matching.

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