Laravel 5:将Model参数传递给中间件 [英] Laravel 5 : passing a Model parameter to the middleware

问题描述

我想将模型参数传递给中间件.根据此链接(laravel 5个中间件参数)，我可以添加一个额外的handle()函数中的参数，如下所示:

I would like to pass a model parameter to a middleware. According to this link (laravel 5 middleware parameters) , I can just include an extra parameter in the handle() function like so :

 public function handle($request, Closure $next, $model)
 {
   //perform actions
 }

如何在控制器的构造函数中传递它?这不起作用:

How would you pass it in the constructor of the Controller? This isn't working :

public function __construct(){
    $model = new Model();
    $this->middleware('myCustomMW', $model);
}

**注意:**重要的是，我可以传递不同的模型(例如ModelX，ModelY，ModelZ)

**NOTE : ** it is important that I could pass different Models (ex. ModelX, ModelY, ModelZ)

推荐答案

首先请确保您使用的是Laravel 5.1.早期版本中没有中间件参数.

First of all make sure that you're using Laravel 5.1. Middleware parameters weren't available in prior versions.

现在，我不相信您可以将实例化的对象作为参数传递给中间件，但是(如果您确实需要)可以在需要特定实例的情况下传递模型的类名和主键.

Now I don't believe you can pass an instantiated object as a parameter to your middleware, but (if you really need this) you can pass a model's class name and i.e. primary key if you need a specific instance.

在您的中间件中:

public function handle($request, Closure $next, $model, $id)
{
    // Instantiate the model off of IoC and find a specific one by id
    $model = app($model)->find($id);
    // Do whatever you need with your model

    return $next($request);
}

在您的控制器中:

use App\User;

public function __construct()
{
    $id = 1; 
    // Use middleware and pass a model's class name and an id
    $this->middleware('myCustomMW:'.User::class.",$id"); 
}

通过这种方法，您可以将所需的任何模型传递给中间件.

With this approach you can pass whatever models you want to your middleware.

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