如何将数据从中间件传递给处理程序? [英] How can I pass data from middleware to handlers?
问题描述
我正在设计我的处理程序以返回http.Handler.这是我的处理程序的设计:
I am designing my handlers to return a http.Handler. Here's the design of my handlers:
func Handler() http.Handler {
return http.HandlerFunc(func(w http.ResponseWriter, r *http.Request) {
})
}
我的中间件被设计为接受http.Handler,然后在中间件完成其操作后调用该处理程序.这是我的中间件的设计:
My middleware is designed to accept an http.Handler and then call the handler once the middleware has finished performing its operations. Here's the design of my middleware:
func Middleware(next http.Handler) http.Handler {
return http.HandlerFunc(func(w http.ResponseWriter, r *http.Request) {
// Middleware operations
next.ServeHTTP(w, r)
})
}
考虑到我的中间件和处理程序的设计,将信息从中间件传递到处理程序的正确方法是什么?我试图从中间件传递给处理程序的信息是从请求正文中解析的JSON Web令牌.如果我没有将解析的JWT传递给处理程序,那么我将需要在处理程序中再次解析JWT.在中间件和处理程序中解析JWT的请求正文似乎很浪费.以防万一这些信息是相关的,我将标准的net/http库与大猩猩mux一起使用.
Considering the design of my middleware and handlers, what is the proper way of passing information from the middleware to the handler? The information that I am trying to pass from my middleware to the handlers is a JSON web token parsed from the request body. If I do not pass the parsed JWT to the handler, then I will need to parse the JWT again in my handlers. Parsing the request body for a JWT in both the middleware and handler seems wasteful. Just in case this information is relevant, I am using the standard net/http library with gorilla mux.
推荐答案
Since you're already using Gorilla take a look at the context package.
(如果您不想更改方法签名,这很好.)
import (
"github.com/gorilla/context"
)
...
func Middleware(next http.Handler) http.Handler {
return http.HandlerFunc(func(w http.ResponseWriter, r *http.Request) {
// Middleware operations
// Parse body/get token.
context.Set(r, "token", token)
next.ServeHTTP(w, r)
})
}
...
func Handler() http.Handler {
return http.HandlerFunc(func(w http.ResponseWriter, r *http.Request) {
token := context.Get(r, "token")
})
}
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