Laravel 5在刀片视图中调用模型函数 [英] Laravel 5 call a model function in a blade view

问题描述

我想从3个表构建刀片视图:

I want to build a blade view from 3 tables:

• "inputs_details"-字段:article_type(值:"p"表示产品，服务是"s")，article_id，....
• 产品"-字段:ID，名称
• 服务"-字段:ID，名称

但是，在浏览器中，出现错误:未找到类'产品'".

But, in browser, I have the error: "Class 'Product' not found".

是否有解决方案可以将此功能传递给视图(根据article_type和article_id查找产品或服务的名称)?

Is there a solution to pass to the view this function (to find the name of the product or the service based on article_type and article_id)?

我也在尝试使用联接查询，但是我无法在单个联接查询中放置太多条件..其中article_type为"p"，然后与"products"表联接...或.... article_type为"s"，然后与服务"表联接.

I was trying also with join query, but I couldn't put so many conditions in a single join query .. where article_type is "p", then join with "products" table ... or .... where article_type is "s", then join with "services" table.

推荐答案

与答案中的问题有关:

您可以通过多种选择来达到更好的效果:

You have multiple options to achieve this that are way better:

假设您有一个传递给视图的模型:

Let's assume you have a model which you pass to the view:

$model = Model::find(1);
View::make('view')->withModel($model);

现在在您的模型中，您可以拥有一个功能:

Now in your Model you could have a function:

public function someFunction() {
    // do something
}

在您看来，您可以直接调用该函数:

In your view you could call that function directly:

{{$model->someFunction()}}

如果您要对模型(数据集)做些事情，这很好.

This is nice if you want to do something with the model (the dataset).

如果没有，您仍然可以在模型中创建静态函数:

If not you can still make a static function in the model:

public static function someStaticFunction($var1, $var2) {
    // do something
}

然后:

{{App\Model::someStaticFunction($yourVar1,$yourVar2)}}

希望有帮助.

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