Laravel 5 在刀片视图中调用模型函数 [英] Laravel 5 call a model function in a blade view

问题描述

我想从 3 个表构建一个刀片视图:

I want to build a blade view from 3 tables:

• "inputs_details" - 字段:article_type(值:'p' 表示产品，'s' 表示服务)、article_id、....
• "products" - 字段:id、name
• "services" - 字段:id、name

但是，在浏览器中，我遇到错误:找不到产品"类.

But, in browser, I have the error: "Class 'Product' not found".

有没有办法把这个函数传递给视图(根据article_type和article_id查找产品或服务的名称)?

Is there a solution to pass to the view this function (to find the name of the product or the service based on article_type and article_id)?

我也尝试使用连接查询，但我无法在单个连接查询中放置这么多条件..其中 article_type 为p"，然后与products"表连接...或.... wherearticle_type 为s"，然后加入services"表.

I was trying also with join query, but I couldn't put so many conditions in a single join query .. where article_type is "p", then join with "products" table ... or .... where article_type is "s", then join with "services" table.

推荐答案

与您回答中的问题相关:

Related to the question in your answer:

您有多种选择可以更好地实现这一目标:

You have multiple options to achieve this that are way better:

假设您有一个传递给视图的模型:

Let's assume you have a model which you pass to the view:

$model = Model::find(1);
View::make('view')->withModel($model);

现在在你的模型中你可以有一个函数:

Now in your Model you could have a function:

public function someFunction() {
    // do something
}

在您看来，您可以直接调用该函数:

In your view you could call that function directly:

{{$model->someFunction()}}

如果你想对模型(数据集)做一些事情，这很好.

This is nice if you want to do something with the model (the dataset).

如果没有，您仍然可以在模型中创建一个静态函数:

If not you can still make a static function in the model:

public static function someStaticFunction($var1, $var2) {
    // do something
}

然后:

{{AppModel::someStaticFunction($yourVar1,$yourVar2)}}

希望有帮助.

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