两个Python对象如何具有相同的ID，但'is'运算符返回False? [英] How can two Python objects have same id but 'is' operator returns False?

问题描述

id(t+t), id(t*2)
(42838592, 42838592)

(t+t) is (t*2)
False

如果两个变量指向同一个对象，则'is'运算符将返回true.但是第一行表示两者具有相同的id，但是'is'运算符给出了错误的值.

If two variable point to same object 'is' operator will return true.But first line said both have same id but 'is' operator give false value.

推荐答案

在第一个示例中，您的对象在时间上没有重叠:创建一个对象，然后销毁它们，然后创建另一个具有相同ID的对象.

In the first example, your objects don't overlap in time: one is created then destroyed, then another is created with the same id.

将它们与is进行比较时，您将同时按住两个对象，因此它们会获得不同的ID.

When you compare them with is, you are holding onto both objects, so they get different ids.

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