如何在霍夫变换后仅过滤最长的行 [英] How to filter only the longest line after Hough Transform
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问题描述
我目前正在使用霍夫变换来获取直线.但是检测到很多线路.我可以知道如何过滤并仅从输出中获取最长的行吗?
I'm currently using the Hough Transform to get the straight lines. But there are a lot of lines detected. Can I know how to filter and only get the longest line from the output?
HoughLinesP(dst, lines, 1, CV_PI/180, 50, 20, 10 ); //left lane
for( size_t i = 0; i < lines.size(); i++ )
{
Vec4i l = lines[i];
double theta1,theta2, hyp, result;
theta1 = (l[3]-l[1]);
theta2 = (l[2]-l[0]);
hyp = hypot(theta1,theta2);
line( cdst, Point(l[0], l[1]), Point(l[2], l[3]), Scalar(255,0,0), 3, CV_AA);
}
imshow("detected lines", cdst);
}
推荐答案
据我所知,您实际上已经走了一步:
As far as I can see, you're literally a step away:
hypot
功能为您提供起点和终点之间的距离.现在,只需找到最长的这样的距离,相应的线就是最长的.
The hypot
function gives you the distance between the start and end points. Now, simply find the longest such distance, and the corresponding line is the longest.
Vec4i max_l;
double max_dist = -1.0;
for( size_t i = 0; i < lines.size(); i++ )
{
Vec4i l = lines[i];
double theta1,theta2, hyp, result;
theta1 = (l[3]-l[1]);
theta2 = (l[2]-l[0]);
hyp = hypot(theta1,theta2);
if (max_dist < hyp) {
max_l = l;
max_dist = hyp;
}
}
// max_l now has the line of maximum length
line( cdst, Point(max_l[0], max_l[1]), Point(max_l[2], max_l[3]), Scalar(255,0,0), 3, CV_AA);
// do something else with max_l
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