匹配后删除到行尾，保持不匹配 [英] Delete to end of line after a match, keep lines not matched

问题描述

我有以下格式的文件:

interesting text-MIB blah blah blah
VERY INTERESTING TEXT
interesting text-MIB blah blah blah

在包含"-MIB"字符串的每一行中，我要删除此字符串之后的文本，直到该行的末尾.

In each line containing the "-MIB" string, I would like to delete the text following this string, until the end of the line.

以下命令似乎可以正常工作:

The following command seems to work as intended:

sed -i -n -e 's/-MIB.*$/-MIB/p' ./myfile

我的问题是它还会删除找不到我的模式的行.在这里，非常有趣的文字"行将被删除.我对sed并不是很熟悉.我究竟做错了什么? sed是否适合这种治疗方法?

My problem is that it also deletes the lines where my pattern is not found. Here, the line "VERY INTERESTING TEXT" would be deleted. I am not really familiar with sed. What am i doing wrong? Is sed appropriate for this kind of treatment?

推荐答案

您需要省略-n选项. 查看 http://www.gnu.org/software /sed/manual/sed.html#index-g_t_002d_002dquiet-7

You need to leave out the -n option. Check out http://www.gnu.org/software/sed/manual/sed.html#index-g_t_002d_002dquiet-7

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