Sed或Grep替换直到模式匹配后的行尾 [英] Sed or Grep to replace until end of line after pattern match

问题描述

我需要在模式匹配后替换所有字符，直到行尾，同时保持匹配的模式

I need to replace all the characters after a pattern match until the end of the line while keeping the matched pattern

    blhablahPATTERN1XXXXXX

应阅读

    blhablahPATTERN1STUFFI_WANT_TO_INSERT

到目前为止，我尝试过的所有操作也删除了PATTERN1 ...

Everything I've tried so far has deleted the PATTERN1 as well...

推荐答案

使用sed

sed -r 's/(PATTERN1).*/\1STUFFI_WANT_TO_INSERT/' file

您需要捕获 PATTERN1 并在替换字符串中使用\1

You need to capture PATTERN1 and use \1 in replacement string

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