sed 只替换完全匹配 [英] Sed replace only exact match

问题描述

我不想在文件中用 Europe12_yesturday 替换像 Europe12 这样的字符串.不更改文件中同样存在的 Europe12-36 字符串.

I wan't to replace a string like Europe12 with Europe12_yesturday in a file. Without changing the Europe12-36 strings that also exists in the file.

我试过了:

$basename=Europe12
sed -i 's/\b$basename\b/${basename}_yesterday/g' file.txt

但这也改变了 Europe12-36 字符串.

but this also changed the Europe12-36 strings.

推荐答案

手动构建您想要的分隔符列表，而不是使用 \b、\W 或 \<.- 不是单词字符(字母数字)的一部分，因此这也与您的其他字符串匹配.所以尝试这样的事情，根据需要扩展列表:[-a-zA-Z0-9].

Manually construct the delimiter list you want instead of using \b, \W or \<. - is not part of the word characters (alphanumericals), so that's why this also matches your other string. So try something like this, expanding the list as needed: [-a-zA-Z0-9].

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