如何对列表列表进行排序? [英] How To Sort A List Of Lists?

问题描述

好的，我有一个列表要排序.首先，一些代码:

Ok, I have a list of lists that I would like to sort. First, some code:

    foreach (var Row in Result)
    {
        foreach (var RowAll in Row.All)
        {
            DataObject.Add(new List<string>() { RowAll.Value1, RowAll.Value2, RowAll.Value3});
            break; 
        }
    }

现在，我想按每个子列表的Value2对父列表进行排序. 这可能吗?如果是这样，我该怎么办?

Now I want to sort the parent list by each child list's Value2. Is this possible? If so, how can I do this?

推荐答案

您可以通过LINQ执行此操作:

You can do this via LINQ:

 // I'm assuming here that "LastCheckin" is defined as List<List<string>> or similar
 // ...

 var sorted = Data.LastCheckin.OrderBy(list => list[1]);

这将返回一个IEnumerable<List<string>>，其中包含按子列表(Value2)中第二个值排序的列表".

This will return an IEnumerable<List<string>> containing your "lists" sorted by the second value in the sub-list (Value2).

如果要对列表进行排序，可以使用 List<T>.Sort 代替:

If you want to sort the list in place, you could use List<T>.Sort instead:

 Data.LastCheckin.Sort( (a,b) => a[1].CompareTo(b[1]) );

如果您需要在运行时指定升序或降序，则一种简单的处理方法是:

If you need to specify, at runtime, ascending or decending, an easy way to handle this is:

 bool ascending = true; // Set to false for decending

 int mult = ascending ? 1 : -1;
 Data.LastCheckin.Sort( (a,b) => mult * a[1].CompareTo(b[1]) );

---

为了处理更复杂的检查，您可以将lambda分成多行:

---

In order to handle more complex checking, you can split your lambda over multiple lines:

 bool ascending = true; // Set to false for decending
 string myDateFormat = GetDateFormat(); // Specify date format

 int mult = ascending ? 1 : -1;
 Data.LastCheckin.Sort( (aStr,bStr) => 
    {
        DateTime a, b;
        bool aSuccess = DateTime.TryParseExact(aStr[1], myDateFormat, DateTimeStyles.None, CultureInfo.InvariantCulture, out a);
        bool bSuccess = DateTime.TryParseExact(bStr[1], myDateFormat, DateTimeStyles.None, CultureInfo.InvariantCulture, out b);

        int result;
        if (!aSuccess)
            result = bSuccess ? -1 : 0;
        else if (!bSuccess)
            result = 1;
        else
            result = a.CompareTo(b);

        return mult * result;

    });

这处理了a和b上的解析器故障，应将它们放在排序的末尾.

This handles parser failures on a and b, and should put them at the end of the sort.

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