按内部列表的特定索引对列表列表进行排序 [英] Sorting list of lists by particular index of inner lists

问题描述

我有一个看起来像这样的列表:

I have a list that looks something like this:

[["Local 7" 1 "say" "Say: Inspect Fences"] ["Local 7" 1 "do" "Do: Shepherd Cows"] ["Local 6" 1 "say" "Say: Shepherd Cows"] ["Local 6" 1 "do" "Do: Shepherd Cows"] ["Local 6" 2 "say" "Say: Shepherd Cows"] ["Local 6" 2 "do" "Do: Shepherd Cows"] ["Local 7" 2 "say" "Say: Inspect Fences"] ["Local 7" 2 "do" "Do: Shepherd Cows"] ["Local 6" 3 "say" "Say: Shepherd Cows"] ["Local 6" 3 "do" "Do: Shepherd Cows"] ["Local 7" 3 "say" "Say: Inspect Fences"] ["Local 7" 3 "do" "Do: Inspect Fences"]]

我想按item 1对列表进行排序. (我知道它已经在复制/粘贴的版本中，但是可能并不总是如此.)

I'd like to sort the list by item 1. (I know it already is in the copy/pasted version, but it might not always be.)

sort只是返回一个空列表(我什至不知道为什么，但是我想那是一个单独的问题)，并且sort-by似乎不起作用，因为它需要一个解析为布尔值的报告器.

sort just returns an empty list (I'm not even sure why, but I guess that's a separate question), and sort-by doesn't seem to work because it needs a reporter that resolves to a boolean.

有一个聪明的方法可以做到这一点吗?还是我需要首先获取要排序的值的列表，然后对其进行排序，然后在该列表上进行迭代，从而在原始列表中创建一个与各个项目值匹配的值的新列表? >

Is there a clever way to do this? Or would I need to first get a list of the values I want to sort by, then sort that, and then iterate over that list, creating a new list of the values in the original list in which the respective item value matches?

推荐答案

使用NetLogo 6语法更新

Updated with NetLogo 6 syntax

您可以轻松地将其转换为sort-by:

You can convert this into a sort-by pretty easily:

to-report sort-with [ key lst ]
  report sort-by [ [a b] -> (runresult key a) < (runresult key b) ] lst
end

然后您像这样使用它:

sort-with [ l -> item 1 l ] my-list

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