使用LINQ读取XML数据，多个具有相同名称的元素 [英] Reading XML data using LINQ, multiple elements with the same name

问题描述

Visual Studio 2010，Silverlight 4和C#.我将以下数据存储在XML文件中:

Visual Studio 2010, Silverlight 4, and C#. I have the following data stored in an XML file:

<root>
      <element>TextHere</element>
      <element>TextHere</element>
      <element>TextHere</element>
</root>

这是我当前的代码.

XDocument xmlDoc = XDocument.Load("XMLDocument.xml");
var ElementsList = from Elements in xmlDoc.Descendants("root")
                   select new
                   {
                       ElementContent = Elements.Element("Element").Value,
                   };

此代码仅将第一个元素放在列表中，而将所有其他元素都排除在外.如何重写此代码，以便捕获XML文件中所有名为元素"的元素?

This code only puts the very first element in the list, leaving all of the others out. How can I rewrite this code so that it will capture ALL of the elements that are named "element" in the XML file?

推荐答案

这可以做到:

XDocument xmlDoc = XDocument.Load("XMLDocument.xml");
var ElementsList = from Elements in xmlDoc.Descendants("element")
                   select new
                   {
                       ElementContent = Elements.Value
                   };

或更简单的点表示法:

var ElementsList = xmlDoc.Descendants("element")
                         .Select(x => new { ElementContent = x.Value });

但是请注意，此后您只有一个元素枚举，如果您想要一个列表(如变量名所示)，则可以在Select之后添加.ToList():

Note however that you only have an enumeration of elements after this, if you want a list (as your variable name suggests) you can add a .ToList() after the Select:

var ElementsList = xmlDoc.Descendants("element")
                         .Select(x => new { ElementContent = x.Value })
                         .ToList();

此列表将包含3个元素(基于您的示例XML. )(具有ElementContent属性的匿名类型).如果您不需要该属性(我想您不需要)，那么这是一个简化版本，只返回字符串列表:

This will list will contain 3 elements (based on your example XML. ) of an anonymous type that has a ElementContent property. If you do not need that property (and I would think you don't) this is a simplified version that just returns a list of string:

var ElementsList = xmlDoc.Descendants("element")
                         .Select(x => x.Value)
                         .ToList();

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