XSLT 1.0分组具有相同名称的多个元素 [英] XSLT 1.0 Grouping with multiple elements with same name

问题描述

我有一个类似-

<resultset>
    <hit>
        <content>
            <ITEM>
                <TITLE>Office Cleaning</TITLE>
                <DESCRIPTION>blah blah blah</DESCRIPTION>
                <Hierarchy>level1A:level2A:level3A</Hierarchy>
                <Hierarchy>level1B:level2B:level3B</Hierarchy>
            </ITEM>
        </content>
    </hit>
    <hit>
        <content>
            <ITEM>
                <TITLE>Office Cleaning1</TITLE>
                <DESCRIPTION>blah blah blah</DESCRIPTION>
                <Hierarchy>level1A:level2A:level3A</Hierarchy>
            </ITEM>
        </content>
    </hit>
    <hit>
        <content>
            <ITEM>
                <TITLE>Office Cleaning2</TITLE>
                <DESCRIPTION>blah blah blah</DESCRIPTION>
                <Hierarchy>level1A:level2B:level3C</Hierarchy>
            </ITEM>
        </content>
    </hit>
</resultset>

请注意，有多个层次结构元素，它们是level1:level2:level3的串联字符串 我希望将其转换为类似的内容-

Note that there are multiple hierarchy elements which is a concatenated string of level1:level2:level3 I am looking to transform this into something like this -

<TREE>
<LEVELS>
<LEVEL1 name="level1A">
 <LEVEL2 name="level2A">
   <LEVEL3 name="level3A">
      <ITEM Name="Office Cleaning"/>
      <ITEM Name="Office Cleaning1"/>
   </LEVEL3>
 </LEVEL2>
</LEVEL1>
<LEVEL1 name="level1B">
 <LEVEL2 name="level2B">
   <LEVEL3 name="level3B">
        <ITEM Name="Office Cleaning"/>
   </LEVEL3>
 </LEVEL2>
</LEVEL1>
<LEVEL1 name="level1A">
 <LEVEL2 name="level2B">
   <LEVEL3 name="level3C">
      <ITEM Name="Office Cleaning2"/>
    </LEVEL3>
 </LEVEL2>
</LEVEL1>
</LEVELS>
</TREE>

基本上，每个项目都具有多个与之相关的层次结构.我需要将它们组合在一起.

Basically each item has multiple hierachy associated with it. I need to group them together.

我只得到-

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:autn="http://schemas.autonomy.com/aci/">

<xsl:output method="xml" omit-xml-declaration="yes"/>

<xsl:key name="HIERARCHYLEVELS" match="resultset/hit/content/ITEM" use="HIERARCHY" />
<xsl:template match="/">
<TREE>

    <xsl:for-each select="resultset/hit/content/ITEM[generate-id()=generate-id(key('HIERARCHYLEVELS', HIERARCHY)[1])]">
        <xsl:for-each select="HIERARCHY">
        <xsl:variable name="level" select="HIERARCHY"/>
        <HIERARCHY name="{$level}" >

            <xsl:variable name="name" select="TITLE"/>

            <ITEM name="{$name}"/>

        </HIERARCHY>
        </xsl:for-each>
    </xsl:for-each>


</TREE>
</xsl:template>

</xsl:stylesheet>

但是问题是我只得到第一个匹配的层次结构标记.例如我看不到办公室清洁1". 我该怎么做才能确保考虑所有层次结构元素?我仍然需要将其分为多个级别.

But the problem is I only get the first matching hierarchy tag. For e.g. I dont get to see "Office cleaning1". What can I do to make sure all hierarchy elements are considered? I still need to split it into various levels.

推荐答案

此转换:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:key name="kItemByHier" match="ITEM" use="Hierarchy"/>
 <xsl:key name="kHierByVal" match="Hierarchy" use="."/>

 <xsl:template match="/*">
     <xsl:apply-templates select=
     "*/*/*/Hierarchy[generate-id()=generate-id(key('kHierByVal',.)[1])]"/>
 </xsl:template>

  <xsl:template match="Hierarchy">
    <xsl:call-template name="makeTree">
      <xsl:with-param name="pHier" select="string()"/>
      <xsl:with-param name="pItems" select="key('kItemByHier', .)"/>
    </xsl:call-template>
  </xsl:template>

  <xsl:template name="makeTree">
    <xsl:param name="pHier"/>
    <xsl:param name="pDepth" select="1"/>
    <xsl:param name="pItems" select="/.."/>

    <xsl:choose>
      <xsl:when test="not($pHier)">
        <xsl:for-each select="$pItems">
          <ITEM name="{TITLE}"/>
        </xsl:for-each>
      </xsl:when>
      <xsl:otherwise>
        <xsl:element name="LEVEL{$pDepth}">
          <xsl:attribute name="name">
            <xsl:value-of select="substring-before(concat($pHier,':'), ':')"/>
          </xsl:attribute>

          <xsl:call-template name="makeTree">
            <xsl:with-param name="pHier" 
                            select="substring-after($pHier,':')"/>
            <xsl:with-param name="pDepth" select="$pDepth+1"/>
            <xsl:with-param name="pItems" select="$pItems"/>
          </xsl:call-template>
        </xsl:element>
      </xsl:otherwise>
    </xsl:choose>
  </xsl:template>
</xsl:stylesheet>

应用于提供的XML文档:

<resultset>
    <hit>
        <content>
            <ITEM>
                <TITLE>Office Cleaning</TITLE>
                <DESCRIPTION>blah blah blah</DESCRIPTION>
                <Hierarchy>level1A:level2A:level3A</Hierarchy>
                <Hierarchy>level1B:level2B:level3B</Hierarchy>
            </ITEM>
        </content>
    </hit>
    <hit>
        <content>
            <ITEM>
                <TITLE>Office Cleaning1</TITLE>
                <DESCRIPTION>blah blah blah</DESCRIPTION>
                <Hierarchy>level1A:level2A:level3A</Hierarchy>
            </ITEM>
        </content>
    </hit>
    <hit>
        <content>
            <ITEM>
                <TITLE>Office Cleaning2</TITLE>
                <DESCRIPTION>blah blah blah</DESCRIPTION>
                <Hierarchy>level1A:level2B:level3C</Hierarchy>
            </ITEM>
        </content>
    </hit>
</resultset>

产生想要的正确结果:

<LEVEL1 name="level1A">
   <LEVEL2 name="level2A">
      <LEVEL3 name="level3A">
         <ITEM name="Office Cleaning"/>
         <ITEM name="Office Cleaning1"/>
      </LEVEL3>
   </LEVEL2>
</LEVEL1>
<LEVEL1 name="level1B">
   <LEVEL2 name="level2B">
      <LEVEL3 name="level3B">
         <ITEM name="Office Cleaning"/>
      </LEVEL3>
   </LEVEL2>
</LEVEL1>
<LEVEL1 name="level1A">
   <LEVEL2 name="level2B">
      <LEVEL3 name="level3C">
         <ITEM name="Office Cleaning2"/>
      </LEVEL3>
   </LEVEL2>
</LEVEL1>

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