Python:在Linux中获取本地接口/IP地址的默认网关 [英] Python: get default gateway for a local interface/ip address in linux

问题描述

在Linux上，如何使用python查找本地IP地址/接口的默认网关?

On Linux, how can I find the default gateway for a local ip address/interface using python?

我看到了一个问题:如何获取UPnP的内部IP，外部IP和默认网关"，但是公认的解决方案仅显示了如何获取Windows网络接口的本地IP地址.

I saw the question "How to get internal IP, external IP and default gateway for UPnP", but the accepted solution only shows how to get the local IP address for a network interface on windows.

谢谢.

推荐答案

对于那些不希望额外依赖并且不喜欢调用子流程的人，这是您直接阅读/proc/net/route的方法: /p>

For those people who don't want an extra dependency and don't like calling subprocesses, here's how you do it yourself by reading /proc/net/route directly:

import socket, struct

def get_default_gateway_linux():
    """Read the default gateway directly from /proc."""
    with open("/proc/net/route") as fh:
        for line in fh:
            fields = line.strip().split()
            if fields[1] != '00000000' or not int(fields[3], 16) & 2:
                continue

            return socket.inet_ntoa(struct.pack("<L", int(fields[2], 16)))

我没有要测试的大字节序计算机，因此我不确定字节序是否取决于您的处理器体系结构，但是如果是，请将struct.pack('<L', ...中的<替换为，因此代码将使用计算机的本地字节序.

I don't have a big-endian machine to test on, so I'm not sure whether the endianness is dependent on your processor architecture, but if it is, replace the < in struct.pack('<L', ... with = so the code will use the machine's native endianness.

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