Linux下C:获取默认接口的IP地址 [英] Linux C: Get default interface's IP address

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问题描述

我的问题是关于以下code(在此链接

My question is about the following code (in this link):

#include <stdio.h>
#include <sys/types.h>
#include <ifaddrs.h>
#include <netinet/in.h>
#include <string.h>
#include <arpa/inet.h>

int main (int argc, const char * argv[]) {
    struct ifaddrs * ifAddrStruct = NULL;
    struct ifaddrs * ifa = NULL;
    void * tmpAddrPtr = NULL;

    getifaddrs(&ifAddrStruct);

    for (ifa = ifAddrStruct; ifa != NULL; ifa = ifa->ifa_next) {
        if (ifa ->ifa_addr->sa_family==AF_INET) { // Check it is
            // a valid IPv4 address
            tmpAddrPtr = &((struct sockaddr_in *)ifa->ifa_addr)->sin_addr;
            char addressBuffer[INET_ADDRSTRLEN];
            inet_ntop(AF_INET, tmpAddrPtr, addressBuffer, INET_ADDRSTRLEN);
            printf("%s IP Address %s\n", ifa->ifa_name, addressBuffer);
        }
        else if (ifa->ifa_addr->sa_family==AF_INET6) { // Check it is
            // a valid IPv6 address
            tmpAddrPtr = &((struct sockaddr_in6 *)ifa->ifa_addr)->sin6_addr;
            char addressBuffer[INET6_ADDRSTRLEN];
            inet_ntop(AF_INET6, tmpAddrPtr, addressBuffer, INET6_ADDRSTRLEN);
            printf("%s IP Address %s\n", ifa->ifa_name, addressBuffer);
        }
    }
    if (ifAddrStruct != NULL)
        freeifaddrs(ifAddrStruct);
    return 0;
}

这code的输出是这样的:

This code's output is like this:

lo IP Address 127.0.0.1
wlan0 IP Address 172.28.1.89 (I want to only this)
lo IP Address ::1
wlan0 IP Address fe80::6e71:d9ff:fe1d:b0

我怎样才能得到默认接口的IP地址? (你可以给另一个code片的答案。)

How can I get the default interface's IP address? (You can give an answer with another code piece.)

推荐答案

这code会做的事:

#include <stdio.h>
#include <unistd.h>
#include <string.h> /* For strncpy */
#include <sys/types.h>
#include <sys/socket.h>
#include <sys/ioctl.h>
#include <netinet/in.h>
#include <net/if.h>
#include <arpa/inet.h>

int
main()
{
    int fd;
    struct ifreq ifr;

    fd = socket(AF_INET, SOCK_DGRAM, 0);

    /* I want to get an IPv4 IP address */
    ifr.ifr_addr.sa_family = AF_INET;

    /* I want an IP address attached to "eth0" */
    strncpy(ifr.ifr_name, "eth0", IFNAMSIZ-1);

    ioctl(fd, SIOCGIFADDR, &ifr);

    close(fd);

    /* Display result */
    printf("%s\n", inet_ntoa(((struct sockaddr_in *)&ifr.ifr_addr)->sin_addr));

    return 0;
}

结果:

192.168.5.27

RUN SUCCESSFUL (total time: 52ms)


另外,你也可以使用一个IP地址掩码。例如,如果面具是从255.0.0.0不同,这将只打印(回送面膜)


Alternatively, you can also use an IP address mask. For example, this will print only if mask is different from 255.0.0.0 (loopback mask)

#include <stdio.h>
#include <sys/types.h>
#include <ifaddrs.h>
#include <netinet/in.h>
#include <string.h>
#include <arpa/inet.h>

int main(int argc, const char * argv[]) {
    struct ifaddrs * ifAddrStruct = NULL, * ifa = NULL;
    void * tmpAddrPtr = NULL;

    getifaddrs(&ifAddrStruct);
    for (ifa = ifAddrStruct; ifa != NULL; ifa = ifa->ifa_next) {
        if (ifa ->ifa_addr->sa_family == AF_INET) { // Check it is IPv4
            char mask[INET_ADDRSTRLEN];
            void* mask_ptr = &((struct sockaddr_in*) ifa->ifa_netmask)->sin_addr;
            inet_ntop(AF_INET, mask_ptr, mask, INET_ADDRSTRLEN);
            if (strcmp(mask, "255.0.0.0") != 0) {
                printf("mask:%s\n", mask);
                // Is a valid IPv4 Address
                tmpAddrPtr = &((struct sockaddr_in *) ifa->ifa_addr)->sin_addr;
                char addressBuffer[INET_ADDRSTRLEN];
                inet_ntop(AF_INET, tmpAddrPtr, addressBuffer, INET_ADDRSTRLEN);
                printf("%s IP Address %s\n", ifa->ifa_name, addressBuffer);
            }
            else if (ifa->ifa_addr->sa_family == AF_INET6) { // Check it is
                // a valid IPv6 Address.

                // Do something
            }
        }
    }
    if (ifAddrStruct != NULL)
        freeifaddrs(ifAddrStruct);
    return 0;
}

结果:

mask:255.255.255.0

eth0 IP Address 192.168.5.27

RUN SUCCESSFUL (total time: 53ms)

这篇关于Linux下C:获取默认接口的IP地址的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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