从$ PATH变量中删除冗余路径 [英] Remove redundant paths from $PATH variable

问题描述

我已经在$ PATH变量中定义了6次相同的路径.

I have defined the same path in the $PATH variable 6 times.

我没有注销以查看它是否有效.

I wasn't logging out to check whether it worked.

如何删除重复项?

$ PATH变量如下:

The $PATH variable looks like this:

echo $PATH

/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/home/flacs/Programmes/USFOS/bin:/home/flacs/Programmes/USFOS/bin:/home/flacs/Programmes/USFOS/bin:/home/flacs/Programmes/USFOS/bin:/home/flacs/Programmes/USFOS/bin:/home/flacs/Programmes/USFOS/bin

我如何将其重置为

/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games

推荐答案

您只需执行:

export PATH=/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games

这将用于当前会话，如果要永久更改，请将其添加到任何.bashrc，bash.bashrc，/etc/profile-适合您系统和用户需求的内容.

that would be for the current session, if you want to change permanently add it to any .bashrc, bash.bashrc, /etc/profile - whatever fits your system and user needs.

注意:这是针对Linux的.对于新的编码器，我们将进行明确说明. (`，')不要尝试SET =这些.

Note: This is for Linux. We'll make this clear for new coders. (` , ') Don't try to SET = these.

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