从 $PATH 变量中删除冗余路径 [英] Remove redundant paths from $PATH variable

问题描述

我在 $PATH 变量中定义了 6 次相同的路径.

I have defined the same path in the $PATH variable 6 times.

我不是为了检查它是否有效而退出.

I wasn't logging out to check whether it worked.

如何删除重复项?

$PATH 变量如下所示:

The $PATH variable looks like this:

echo $PATH

/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/home/flacs/Programmes/USFOS/bin:/home/flacs/Programmes/USFOS/bin:/home/flacs/Programmes/USFOS/bin:/home/flacs/Programmes/USFOS/bin:/home/flacs/Programmes/USFOS/bin:/home/flacs/Programmes/USFOS/bin

我如何将其重置为只是

/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games

推荐答案

你只需执行:

export PATH=/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games

这将用于当前会话，如果您想永久更改，请将其添加到任何 .bashrc、bash.bashrc、/etc/profile - 任何适合您的系统和用户需求的文件.

that would be for the current session, if you want to change permanently add it to any .bashrc, bash.bashrc, /etc/profile - whatever fits your system and user needs.

注意:这是针对 Linux 的.我们将为新编码人员明确这一点.(` , ') 不要尝试 SET = 这些.

Note: This is for Linux. We'll make this clear for new coders. (` , ') Don't try to SET = these.

这篇关于从 $PATH 变量中删除冗余路径的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！