递归查找比给定时间新的所有文件 [英] Recursively find all files newer than a given time

问题描述

给出一个time_t:

Given a time_t:

⚡ date -ur 1312603983
Sat  6 Aug 2011 04:13:03 UTC

我正在寻找一种bash单线版，其中列出了所有较新的文件.比较时应考虑时区.

I'm looking for a bash one-liner that lists all files newer. The comparison should take the timezone into account.

类似

find . --newer 1312603983

但是使用time_t而不是文件.

But with a time_t instead of a file.

推荐答案

这有点circuit回，因为touch不会使用原始的time_t值，但它应该在脚本中相当安全地完成工作. (date的-r选项在MacOS X中存在；我没有仔细检查过GNU.)可以通过直接在touch命令行中编写命令替换来避免使用"time"变量. >

This is a bit circuitous because touch doesn't take a raw time_t value, but it should do the job pretty safely in a script. (The -r option to date is present in MacOS X; I've not double-checked GNU.) The 'time' variable could be avoided by writing the command substitution directly in the touch command line.

time=$(date -r 1312603983 '+%Y%m%d%H%M.%S')
marker=/tmp/marker.$$
trap "rm -f $marker; exit 1" 0 1 2 3 13 15
touch -t $time $marker
find . -type f -newer $marker
rm -f $marker
trap 0

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