使用TAR归档时如何剥离路径 [英] How to strip path while archiving with TAR

问题描述

我有一个文件，其中包含要使用tar存档的文件列表. 我们称之为mylist.txt

I have a file that contain list of files I want to archive with tar. Let's call it mylist.txt

它包含:

/path1/path2/file1.txt
/path1/path2/file3.txt
...
/path1/path2/file10.txt

我要做的是将此文件归档到tarball中，但不包括/path1/path2/. 目前正在执行此操作:

What I want to do is to archive this file into a tarball but excluding /path1/path2/. Currently by doing this:

tar -cvf allfiles.tar -T mylist.txt

取消存档后保留路径.

我尝试了此操作，但也无法正常工作

I tried this but won't work too:

tar -cvf -C /path1/path2 allfiles.tar -T mylist.txt

它会将/path1/path2中的所有文件存档，即使那些不在mylist.txt中的文件也是如此

It archives all the files in /path1/path2 even those which are not in mylist.txt

有办法吗?

推荐答案

在提取阶段"中，您可以使用strip-components标志，例如

In your "Extraction phase" you can use the strip-components flag like

tar xvf tarname.tar --strip-components=n

这将删除文件名的前n个前导组成部分.尽管如果您使用不同的文件路径组件，则并非在所有情况下都行得通.

which will remove the first n leading components of the file name. Although if you have different file-path-components this will not work for all cases.

如果您想在归档时执行此操作，则只会想到一件事，我将与您分享

If you want to do it while archiving, only one thing comes to mind, and I will share

输入:文件列表+完整路径

INPUT: list of files + full paths

1)每行，将路径从文件名中分离出来

1) for each line, split the path out of the filename

2)执行cd到该路径，并在该文件名上执行tar

2) execute cd to that path and tar on that filename

3)对每一行重复

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