如何在bash中用多行排序? [英] How to sort with multiple lines in bash?

问题描述

我正在尝试对名称列表进行排序，后跟另一个字符串，例如:

I am trying to sort a list of names followed by another string such as:

John Doe
AVAIL

Sara Doe
CALL

Jim Doe
AVAIL

我正在尝试按名称对它们进行排序，但似乎无法通过排序来解决.有人可以提供一些指导吗?

I am trying to sort these by name but can't seem to figure it out with sort. Can someone provide some guidance?

我的最终输出看起来像这样:

My final output would look like this:

Jim Doe
AVAIL

John Doe
AVAIL

Sara Doe
CALL

非常感谢！

推荐答案

可能远非最优，但

sed -r ':r;/(^|\n)$/!{$!{N;br}};s/\n/\v/g' names | sort | sed 's/\v/\n/g'

似乎可以完成这项工作(names是带有记录的文件).这样可以记录任意长度的记录，而不仅仅是2行.

seems to do the job (names is the file with records). This allows records of arbitrary length, not just 2 lines.

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