在Bash中用数字对字符串进行排序 [英] Sorting strings with numbers in Bash

问题描述

我经常想对带有数字的字符串进行排序，以便在排序时abc_2, abc_1, abc_10结果为abc_1, abc_2, abc_10.我见过的每种排序机制都按abc_1, abc_10, abc_2进行排序，即从左开始逐个字符地排序.

I've often wanted to sort strings with numbers in them so that, when sorting e.g. abc_2, abc_1, abc_10 the result is abc_1, abc_2, abc_10. Every sort mechanism I've seen sorts as abc_1, abc_10, abc_2, that is character by character from the left.

是否有任何有效的方法来排序以获得所需的结果?查看每个字符，确定它是否为数字，然后从后续数字中构建一个子字符串，然后根据数字进行排序的想法太令人震惊了，无法在bash中进行考虑.

Is there any efficient way to sort to get the result I want? The idea of looking at every character, determining if it's a numeral, building a substring out of subsequent numerals and sorting on that as a number is too appalling to contemplate in bash.

没有胡子的* nix大师使用--sensible_numerical选项实现了sort的替代版本吗?

Has no bearded *nix guru implemented an alternative version of sort with a --sensible_numerical option?

推荐答案

执行此操作

sort -t _ -k 2 -g data.file

• -t分隔符
• -k键/列
• -g常规数字排序

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