如何从 Bash 对包含公共前缀和后缀的字符串进行数字排序? [英] How to sort strings that contain a common prefix and suffix numerically from Bash?

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问题描述

这是一个文件列表:

some.string_100_with_numbers.in-it.txt
some.string_101_with_numbers.in-it.txt
some.string_102_with_numbers.in-it.txt
some.string_23_with_numbers.in-it.txt
some.string_24_with_numbers.in-it.txt
some.string_25_with_numbers.in-it.txt

现在我想按数字对它进行排序.以*23*开头,以*102*结尾.

Now I would like to sort it numerically. Starting with *23* and ending with *102*.

我尝试过 -n-g.-t 对这些乱七八糟的字符串没有帮助.

I have tried -n and -g. -t does not help in these messy strings.

我可以使用选项忽略数字的前导字符串,还是我必须聪明和脚本?

Can I ignore leading strings to the number with an option or do I have to be clever and script?

推荐答案

使用 ls -lv

来自手册页:

-v     natural sort of (version) numbers within text

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