试图在Yii中获得非对象错误的属性 [英] Trying to get property of non-object error in Yii

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本文介绍了试图在Yii中获得非对象错误的属性的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

案例1:我得到一个CActiveRecords数组,并尝试遍历它,如下所示:

Case 1: I get an array of CActiveRecords and try to loop over it as shown below:

foreach ($pendingTasks as $task)
    {
        if($task->task->employee_id=="1")
        {
            //some logic here
        }
    }

我得到试图获取非对象的属性"

I get "Trying to get property of non-object "

情况2:如果我尝试:

$pendingTasks = TaskLog::model()->findByPk("1");
    if($pendingTasks->task->employee_id=="1")
    {
        //some logic here   
    }

这有效. 为什么会这样呢?我在这里做错什么了吗?

This works. Why is this so? Am I doing any thing wrong here?

推荐答案

由于$pendingTasks中的tasks一定没有关系.您可以像这样简单地添加isset()来进行检查:

Because of the tasks in $pendingTasks must not have a relation. You can check by simply adding an isset() like so:

foreach ($pendingTasks as $task) {
    if(isset($task->task) && $task->task->employee_id=="1") {
        //some logic here
    } else {
        echo "{$task->id} doesn't have a task relation";
    }
}

假设$pendingTasks也是TaskLog的实例.

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