比较Linux中的两个未排序列表，在第二个文件中列出唯一列表 [英] Comparing two unsorted lists in linux, listing the unique in the second file

问题描述

我有2个文件，上面有数字列表(电话号码).

I have 2 files with a list of numbers (telephone numbers).

我正在寻找一种列出第一个文件中不存在的第二个文件中数字的方法.

I'm looking for a method of listing the numbers in the second file that is not present in the first file.

我尝试了以下各种方法:

I've tried the various methods with:

comm (getting some weird sorting errors)
fgrep -v -x -f second-file.txt first-file.txt (unsure of the result, there should be more)

推荐答案

grep -Fxv -f first-file.txt second-file.txt

基本上在second-file.txt中查找与first-file.txt中的任何行都不匹配的所有行.如果文件很大，可能会变慢.

Basically looks for all lines in second-file.txt which don't match any line in first-file.txt. Might be slow if the files are large.

此外，对文件排序后(如果为数字，请使用sort -n)，那么comm也应该起作用.这会带来什么错误?试试这个:

Also, once you sort the files (Use sort -n if they are numeric), then comm should also have worked. What error does it give? Try this:

comm -23 second-file-sorted.txt first-file-sorted.txt

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