Linux上的Java Runtime.exec()参数 [英] Java Runtime.exec() arguments on Linux

问题描述

好的，这是问题所在: 我有3个类MyClass1和MyClass2和ExecClass. 我进入命令提示符并执行以下操作:

Okay so here is the problem: I have 3 classes MyClass1 and MyClass2 and ExecClass. I go to my command prompt and do this:

$java MyClass1 -exec "java MyClass2 arg1 arg2"

效果很好. 现在在ExecClass中，我有以下一行:

which works perfectly. Now in ExecClass I have the following line:

Runtime.getRuntime().exec("java MyClass1 -exec \"java MyClass2 arg1 arg2\"");

问题是，如果您打印第二个字符串，它与第一个字符串完全相同，但是当我的ExecClass运行它时，MyClass1会抱怨:无法识别的参数arg1失败. 经过一番调试后，我发现在第一种情况下，当我直接从终端调用时，引号中的整个字符串是1个参数(arg [1])，在第二种情况下，arg.length = 5且它基本上将它们分割了...出于某种未知的原因. 我只需要知道一个工作环境，如果有人知道，也可以运行我的Runtime.exec()即可. PS:在我的Windows计算机上，这种问题仅在linux上不会发生.这是一个Ubuntu破坏内核:2.6.32-279.14.1.el6.x86_64.

Problem is if you print the second string its exactly the same as the first, but when my ExecClass runs it MyClass1 complains: Unrecognized argument arg1 and fails. After a bit of debugging I found out that in the first case when I'm calling directly from the terminal the whole string in the quotes is 1 argument (arg[1]), where in the second case the arg.length = 5 and it basically splits them... for some unkown reason to me. I just need to know a workarround that if someone knows, aka my Runtime.exec() to works. PS: On my Windows machine such problem does not occur only on the linux. It's a ubuntu destrution Kernel: 2.6.32-279.14.1.el6.x86_64.

推荐答案

Runtime.exec与其他语言中类似system()的函数不同，它不会调用shell来解析命令(并且双引号字符串是shell的功能) ).

Runtime.exec, unlike system()-like functions in other languages, does not invoke a shell to parse the command (and double quoted strings are a shell feature).

要按所需方式拆分字符串，请使用接受String数组的Runtime.exec:

To split the string the way you want it, use the Runtime.exec that accepts a String array:

Runtime.getRuntime().exec(new String[] { "java", "MyClass1", "-exec", "java MyClass2 arg1 arg2"});

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