java Runtime.exec运行shell脚本 - 无法打开文件 [英] java Runtime.exec to run shell script - cannot open file

问题描述

我正在使用Runtime.getRuntime（）。exec（）从java代码运行shell脚本。

I am using Runtime.getRuntime().exec() to run a shell script from java code.

    String[] cmd = {"sh",  "build.sh", "/Path/to my/sh file"};
    try{
        Process proc = Runtime.getRuntime().exec( cmd );
    }
    catch(Exception e){
        System.out.println("Exception is:"+e);
    }

它在控制台中给出了以下输出：

It gives me the following output in console:

sh: Can't open build.sh

我在这里采取了一些错误的做法吗？无法理解为什么会发生这种情况。

Am I following some wrong approach here? Cannot make out why his happens.

编辑

根据此处的评论，我修改了 String [] cmd = {sh，build.sh，/ Path / to my / sh file}; 改为 String [] cmd = {sh，/ Path / to my / sh file / build.sh，/ Path / to my / sh file}; 。现在问题是这个脚本需要从特定路径执行。当我从命令提示符执行此脚本时，我首先将目录更改为该路径并执行它。我该如何修改此代码？

Based on the comment here, I have modified the String[] cmd = {"sh", "build.sh", "/Path/to my/sh file"}; to String[] cmd = {"sh", "/Path/to my/sh file/build.sh", "/Path/to my/sh file"}; . Now the problem is this script need to be executed from a particular path. When I execute this script from command prompt, I first change the directory to that path and execute it. How should I modify this code?

推荐答案

使用 ProcessBuilder 并设置进程的工作目录到你的脚本实际所在的目录：

Use a ProcessBuilder and set the working directory of the process to the directory where your script actually is:

final ProcessBuilder pb = new ProcessBuilder("/bin/sh", "script.sh", "whatever",
    "arguments", "go", "here");
pb.directory(new File("/path/to/directory"));
// redirect stdout, stderr, etc
final Process p = pb.start();

参见 ProcessBuilder javadoc 。它包含了您可以执行的操作的示例。 Runtime.exec（）是passé：p

See the ProcessBuilder javadoc. It contains an example of what you can do. Runtime.exec() is passé :p

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