将字符串分解为Python中的字符列表 [英] Break string into list of characters in Python

问题描述

基本上，我想从文件中吸收一行文本，将字符分配给列表，并创建列表中所有单独字符的列表-列表列表.

Essentially I want to suck a line of text from a file, assign the characters to a list, and create a list of all the separate characters in a list -- a list of lists.

此刻，我已经尝试过:

fO = open(filename, 'rU')
fL = fO.readlines()

这就是我所拥有的.我不太了解如何提取单个字符并将其分配到新列表中.

That's all I've got. I don't quite know how to extract the single characters and assign them to a new list.

我从文件中得到的行将类似于:

The line I get from the file will be something like:

fL = 'FHFF HHXH XXXX HFHX'

我想把它变成这个列表，每个单独的字符都单独出现:

I want to turn it into this list, with each single character on its own:

['F', 'H', 'F', 'F', 'H', ...]

推荐答案

字符串是可迭代的(就像列表一样).

Strings are iterable (just like a list).

我是在解释您确实想要像这样的东西:

I'm interpreting that you really want something like:

fd = open(filename,'rU')
chars = []
for line in fd:
   for c in line:
       chars.append(c)

或

fd = open(filename, 'rU')
chars = []
for line in fd:
    chars.extend(line)

或

chars = []
with open(filename, 'rU') as fd:
    map(chars.extend, fd)

字符将包含文件中的所有字符.

chars would contain all of the characters in the file.

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