如何计算句子中的单词数量，而忽略数字，标点符号和空格? [英] How to count the number of words in a sentence, ignoring numbers, punctuation and whitespace?

问题描述

我该如何计算句子中的单词数?我正在使用Python.

How would I go about counting the words in a sentence? I'm using Python.

例如，我可能具有字符串:

For example, I might have the string:

string = "I     am having  a   very  nice  23!@$      day. "

那将是7个字.我在每个单词之后/之前以及涉及数字或符号时的随机空格有麻烦.

That would be 7 words. I'm having trouble with the random amount of spaces after/before each word as well as when numbers or symbols are involved.

推荐答案

str.split() 不带任何参数的字符会在运行空白字符时分裂:

str.split() without any arguments splits on runs of whitespace characters:

>>> s = 'I am having a very nice day.'
>>> 
>>> len(s.split())
7

从链接的文档中:

如果未指定 sep 或None，则应用不同的拆分算法:连续空格的运行被视为单个分隔符，并且结果开头将不包含空字符串或如果字符串具有前导或尾随空格，则结束.

If sep is not specified or is None, a different splitting algorithm is applied: runs of consecutive whitespace are regarded as a single separator, and the result will contain no empty strings at the start or end if the string has leading or trailing whitespace.

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