如何获得n个二进制值的所有组合? [英] How to get all combination of n binary value?

问题描述

在Python中，如何获取n二进制值0和1的所有组合?

In Python, how can I get all combinations of n binary values 0 and 1?

例如，如果n = 3，我想拥有

[ [0,0,0], [0,0,1], [0,1,0], [0,1,1], ... [1,1,1] ]  #total 2^3 combinations

我该怎么做?

推荐答案

使用 itertools.product

import itertools
lst = list(itertools.product([0, 1], repeat=3))

这将产生一个元组列表(请参见此处)

This will yield a list of tuples (see here)

您可以轻松地将其更改为使用变量repeat:

You can easily change this to use a variable repeat:

n = 3
lst = list(itertools.product([0, 1], repeat=n))

如果需要列表列表，则可以使用map函数(感谢@Aesthete).

If you need a list of lists, then you can use the map function (thanks @Aesthete).

lst = map(list, itertools.product([0, 1], repeat=n))

或者在Python 3中:

Or in Python 3:

lst = list(map(list, itertools.product([0, 1], repeat=n)))
# OR
lst = [list(i) for i in itertools.product([0, 1], repeat=n)]

请注意，使用map或列表理解功能意味着您无需将产品转换为列表，因为它将迭代itertools.product对象并生成列表.

Note that using map or a list comprehension means you don't need to convert the product into a list, as it will iterate through the itertools.product object and produce a list.

这篇关于如何获得n个二进制值的所有组合?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！