如何通过空格字符在列表中拆分字符串 [英] How to split strings inside a list by whitespace characters

问题描述

因此，stdin将一串文本返回到列表中，并且多行文本都是列表元素. 您如何将它们全部分割成一个单词?

So stdin returns a string of text into a list, and multiple lines of text are all list elements. How do you split them all into single words?

mylist = ['this is a string of text \n', 'this is a different string of text \n', 'and for good measure here is another one \n']

想要的输出:

newlist = ['this', 'is', 'a', 'string', 'of', 'text', 'this', 'is', 'a', 'different', 'string', 'of', 'text', 'and', 'for', 'good', 'measure', 'here', 'is', 'another', 'one']

推荐答案

您可以使用简单的列表理解，例如:

You can use simple list comprehension, like:

newlist = [word for line in mylist for word in line.split()]

这会生成:

>>> [word for line in mylist for word in line.split()]
['this', 'is', 'a', 'string', 'of', 'text', 'this', 'is', 'a', 'different', 'string', 'of', 'text', 'and', 'for', 'good', 'measure', 'here', 'is', 'another', 'one']

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