N的总和列出按元素排列的python [英] sum of N lists element-wise python

问题描述

是否有一种简单的方法来计算python中N个列表的元素方式总和?我知道如果我们有n个定义为 的列表(称为ith列表c_i)，我们可以做到:

Is there an easy way to compute the element-wise sum of N lists in python? I know if we have n lists defined (call the ith list c_i), we can do:

z = [sum(x) for x in zip(c_1, c_2, ...)]

例如:

c1 = [1,2]
c2 = [3,4]
c3 = [5,6]
z  = [sum(x) for x in zip(c1,c2,c3)]

此处z = [9, 12]

但是如果我们没有定义c_i而是在列表C中有c_1...c_n怎么办?

But what if we don't have c_i defined and instead have c_1...c_n in a list C?

如果我们只有C，是否有类似的方法来找到z?

Is there a similar way to find z if we just have C?

我希望这很清楚.

已解决:我想知道*运算符到底是关于...谢谢的！

resolved: I was wondering what the * operator was all about...thanks!

推荐答案

只需执行以下操作:

[sum(x) for x in zip(*C)]

在上面，C是c_1...c_n的列表.如评论中链接所述(感谢@ kevinsa5！):

In the above, C is the list of c_1...c_n. As explained in the link in the comments (thanks, @kevinsa5!):

*是"splat"运算符:它将一个列表作为输入，并将其扩展为函数调用中的实际位置参数.

* is the "splat" operator: It takes a list as input, and expands it into actual positional arguments in the function call.

有关其他详细信息，请参见文档，在解压缩参数列表"下，还阅读有关调用(谢谢，@ abarnert！)

For additional details, take a look at the documentation, under "unpacking argument lists" and also read about calls (thanks, @abarnert!)

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