将字符串转换为列表之类的嵌套结构 [英] Convert string to nested structures like list

问题描述

我有一个类似

str_sample = "[[1, 2], [2.0, 0.3], ['a', 'b', [None, (1, 3)], {'c': 'd'}]]"

我当前正在使用:

exec("str2list_sample = "+ str_sample)

有没有更清洁的方法呢?

Is there any much more cleaner approach of doing this?

推荐答案

首先不要命名您的变量str，因为它隐藏了内置变量.

Firstly don't name your variable str as it shadows the built-in.

要解决您的问题，您可以使用 ast.literal_eval

To solve your problem you can use ast.literal_eval

>>> a = "[[1, 2], [2.0, 0.3], ['a', 'b']]"
>>> import ast
>>> ast.literal_eval(a)
[[1, 2], [2.0, 0.3], ['a', 'b']]

解决您的最新修改

>>> str_sample = "[[1, 2], [2.0, 0.3], ['a', 'b', [None, (1, 3)], {'c': 'd'}]]"
>>> ast.literal_eval(str_sample)
[[1, 2], [2.0, 0.3], ['a', 'b', [None, (1, 3)], {'c': 'd'}]]

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