如果条件为真，则创建具有相邻列表元素的元组列表 [英] Create a list of tuples with adjacent list elements if a condition is true

问题描述

我正在尝试创建一个元组列表，其中元组内容是数字9和列表中之前的数字.

I am trying to create a list of tuples where the tuple contents are the number 9 and the number before it in the list.

输入列表:

myList = [1, 8, 9, 2, 4, 9, 6, 7, 9, 8]

所需的输出:

sets = [(8, 9), (4, 9), (7, 9)]

代码:

sets = [list(zip(myList[i:i], myList[-1:])) for i in myList if i==9]

当前结果:

[[], [], []]

推荐答案

更干净的Python方法:

Cleaner Pythonic approach:

>>> [(x,y) for x,y in zip(myList, myList[1:]) if y == 9]
[(8, 9), (4, 9), (7, 9)]

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上面的代码是做什么的

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What is the code above doing:

• zip(some_list, some_list[1:])会生成一对相邻元素的列表.
• 现在有了该元组，请在第二个元素等于9的条件下进行过滤.您完成了:)

• zip(some_list, some_list[1:]) would generate a list of pairs of adjacent elements.
• Now with that tuple, filter on the condition that the second element is equal to 9. You're done :)

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