如果满足某些条件，则从元组列表中删除元组 [英] Remove tuple from list of tuples if certain condition is met

问题描述

我有一个看起来像这样的元组列表；

I have a list of tuples that look like this;

ListTuples = [(100, 'AAA'), (80, 'BBB'), (20, 'CCC'), (40, 'DDD')]

当元组的第一个元素小于 50 时，我想删除元组.OutputList 将如下所示；

I want to remove the tuples when the first element of the tuple is less than 50. The OutputList will look like this;

OutputList = [(100, 'AAA'), (80, 'BBB')]

这在python中如何实现?

How can this be done in python?

非常感谢您的帮助.

推荐答案

您可以轻松地做到:

out_tup = [i for i in in_tup if i[0] >= 50]

[Out]: [(100, 'AAA'), (80, 'BBB')]

这只是创建一个新的元组列表，其中仅包含第一个元素大于或等于 50 的那些元组.结果相同，但方法不同.您接受有效的元组而不是删除无效的元组.

This simply creates a new list of tuples with only those tuples whose first element is greater than or equal to 50. Same result, however the approach is different. Instead of removing invalid tuples you accept the valid ones.

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