如何按字符串的最后一个字符对列表进行排序 [英] How to sort a list by last character of string

问题描述

我正在尝试编写一个程序，该程序根据项目中的最后一个字符对字符串列表进行排序.

I am trying to write a program that orders a list of strings based on the last character in the item.

["Tiger 6", "Shark 4", "Cyborg 8"]是我的列表的导入方式，但是我需要根据末尾的数字将它们按数字顺序放置.

["Tiger 6", "Shark 4", "Cyborg 8"] are how my list is imported, but I need to put them in numerical order based on the numbers at the end.

推荐答案

我正在尝试编写一个程序，该程序根据项目中的最后一个字符对字符串列表进行排序.

I am trying to write a program that orders a list of strings based on the last character in the item.

>>> s = ["Tiger 6", "Shark 4", "Cyborg 8"]
>>> sorted(s, key=lambda x: int(x[-1]))
['Shark 4', 'Tiger 6', 'Cyborg 8']

如果最后有更多数字，请尝试此操作.

Try this if there are more num of digits at the last.

>>> import re
>>> sorted(s, key=lambda x: int(re.search(r'\d+$',x).group()))
['Shark 4', 'Tiger 6', 'Cyborg 8']

re.search(r'\d+$',x).group()有助于获取最后一个存在的数字，而与前面的空格无关.

re.search(r'\d+$',x).group() helps to fetch the number present at the last irrespective of preceding space.

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