如何对列表进行排序，仅对字符串进行排序? [英] How to sort a list, only sorting strings?

问题描述

我有一个字符串和整数列表，想要对列表进行排序，并像这样保留数字

I have a list of strings and integers and want to sort the list, preserving the numbers like so

["Hello", 1, 2, "World", 6, "Foo", 3]

将成为

["Foo", 1, 2, "Hello", 6, "World", 3]

简而言之，它仅对列表中的字符串进行排序，而不对保留在原位的整数进行排序.我尝试将key参数与list.sort()一起使用，但未能实现我想要的.

In short, it only sorts the strings in the list, not the integers, which stay in place. I've tried using the key parameter with list.sort() but haven't managed to achieve what I want.

有人可以帮我吗?

这与链接的问题不同，因为我想保留整数的索引，而不是将它们与字符串一起排序.

this is different to the linked question as I want to preserve the integers' indexes, rather than sort them along with the strings.

这与第二个链接的问题不同，因为该问题的答案可以使用key参数解决问题，我明确声明的内容在这种情况下不起作用.

this is different to the second linked question as answers from that question can solve the problem using the key parameter, something I have explicitly stated does not work in this instance.

推荐答案

前几天从@JonClements挑选了这个很棒的技巧.

Picked up this cool trick from @JonClements the other day.

在这里:

gen = iter(sorted([x for x in lst if isinstance(x, str)]))
new_lst =  [next(gen) if isinstance(x, str) else x for x in lst]
print(new_lst)
# ['Foo', 1, 2, 'Hello', 6, 'World', 3]

分别对字符串进行排序，然后根据排序后的字符串创建生成器表达式.在列表理解中，从gen中交替选择对象.经验如果只有原始位置中的项目是字符串，则使用三元条件，否则，请从初始列表中选择一个项目(整数).

Sort the strings separately and create a generator expression from the sorted strings. In a list comprehension, pick objects alternately from the gen. exp. using a ternary conditional if only the items in the original position is a string, otherwise, pick an item (an integer) from the initial list.

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