按x然后按y对字典列表进行排序 [英] sort a list of dicts by x then by y

问题描述

我想对这些信息(名称，点和时间)进行排序:

I want to sort this info(name, points, and time):

list = [
    {'name':'JOHN', 'points' : 30, 'time' : '0:02:2'},
    {'name':'KARL','points':50,'time': '0:03:00'}
]

所以，我想要的是该列表首先按得分排序，然后按游戏时间排序(在我的示例中，由于他的时间少，所以亚光先走了.有什么帮助吗?

so, what I want is the list sorted first by points made, then by time played (in my example, matt go first because of his less time. any help?

我正在尝试:

import operator
list.sort(key=operator.itemgetter('points', 'time'))

但得到了TypeError: list indices must be integers, not str.

推荐答案

您的示例对我有用.我建议您不要使用list作为变量名，因为它是内置类型.

Your example works for me. I would advise you not to use list as a variable name, since it is a builtin type.

您也可以尝试执行以下操作:

You could try doing something like this also:

list.sort(key=lambda item: (item['points'], item['time']))

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